As opposed to having it print to stdout. Here’s how…
--- httplib.py.orig 2008-12-16 19:14:07.000000000 -0600 +++ httplib.py 2008-12-16 19:26:20.000000000 -0600 @@ -69,6 +69,7 @@ import errno import mimetools import socket +import logging from urlparse import urlsplit try: @@ -342,7 +343,7 @@ # Initialize with Simple-Response defaults line = self.fp.readline() if self.debuglevel > 0: - print "reply:", repr(line) + logging.info("reply: %r" % (line,)) if not line: # Presumably, the server closed the connection before # sending a valid response. @@ -391,7 +392,7 @@ if not skip: break if self.debuglevel > 0: - print "header:", skip + logging.info('header: %r' % (skip,)) self.status = status self.reason = reason.strip() @@ -414,7 +415,7 @@ self.msg = HTTPMessage(self.fp, 0) if self.debuglevel > 0: for hdr in self.msg.headers: - print "header:", hdr, + logging.info('header: %r' % (hdr,)) # don't let the msg keep an fp self.msg.fp = None @@ -665,11 +666,11 @@ try: self.sock = socket.socket(af, socktype, proto) if self.debuglevel > 0: - print "connect: (%s, %s)" % (self.host, self.port) + logging.info("connect: (%s, %s)" % (self.host, self.port)) self.sock.connect(sa) except socket.error, msg: if self.debuglevel > 0: - print 'connect fail:', (self.host, self.port) + logging.info('connect fail:', (self.host, self.port)) if self.sock: self.sock.close() self.sock = None @@ -702,7 +703,7 @@ # NOTE: we DO propagate the error, though, because we cannot simply # ignore the error... the caller will know if they can retry. if self.debuglevel > 0: - print "send:", repr(str) + logging.info("send: %s" % (str,)) try: self.sock.sendall(str) except socket.error, v: